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2x^2+97x+520=0
a = 2; b = 97; c = +520;
Δ = b2-4ac
Δ = 972-4·2·520
Δ = 5249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(97)-\sqrt{5249}}{2*2}=\frac{-97-\sqrt{5249}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(97)+\sqrt{5249}}{2*2}=\frac{-97+\sqrt{5249}}{4} $
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